113314301 has 2 divisors, whose sum is σ = 113314302. Its totient is φ = 113314300.

The previous prime is 113314297. The next prime is 113314303. The reversal of 113314301 is 103413311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101404900 + 11909401 = 10070^2 + 3451^2 .

It is an emirp because it is prime and its reverse (103413311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113314301 - 2² = 113314297 is a prime.

It is a super-2 number, since 2×113314301² = 25680261622237202, which contains 22 as substring.

Together with 113314303, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 113314301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113314303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56657150 + 56657151.

It is an arithmetic number, because the mean of its divisors is an integer number (56657151).

Almost surely, 2^113314301 is an apocalyptic number.

It is an amenable number.

113314301 is a deficient number, since it is larger than the sum of its proper divisors (1).

113314301 is an equidigital number, since it uses as much as digits as its factorization.

113314301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 113314301 is about 10644.9190227075. The cubic root of 113314301 is about 483.9066325488.

Adding to 113314301 its reverse (103413311), we get a palindrome (216727612).

The spelling of 113314301 in words is "one hundred thirteen million, three hundred fourteen thousand, three hundred one".