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1133200151 is a prime number
BaseRepresentation
bin100001110001011…
…0100001100010111
32220222022112100222
41003202310030113
54310044401101
6304240224555
740040020346
oct10342641427
92828275328
101133200151
11531731056
1227760b15b
13150a06445
14aa701b5d
156974301b
hex438b4317

1133200151 has 2 divisors, whose sum is σ = 1133200152. Its totient is φ = 1133200150.

The previous prime is 1133200121. The next prime is 1133200153. The reversal of 1133200151 is 1510023311.

It is a strong prime.

It is an emirp because it is prime and its reverse (1510023311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1133200151 - 210 = 1133199127 is a prime.

It is a Sophie Germain prime.

Together with 1133200153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1133200153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566600075 + 566600076.

It is an arithmetic number, because the mean of its divisors is an integer number (566600076).

Almost surely, 21133200151 is an apocalyptic number.

1133200151 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133200151 is an equidigital number, since it uses as much as digits as its factorization.

1133200151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 1133200151 is about 33663.0383506896. The cubic root of 1133200151 is about 1042.5627597471.

Adding to 1133200151 its reverse (1510023311), we get a palindrome (2643223462).

The spelling of 1133200151 in words is "one billion, one hundred thirty-three million, two hundred thousand, one hundred fifty-one".