Base | Representation |
---|---|
bin | 1010010011100111010111… |
… | …0111001010110011101111 |
3 | 1111010100010121111201202112 |
4 | 2210321311313022303233 |
5 | 2441131120341421221 |
6 | 40033521223114235 |
7 | 2246501013150533 |
oct | 244716567126357 |
9 | 44110117451675 |
10 | 11332101123311 |
11 | 3679a0a725291 |
12 | 13302a18a297b |
13 | 6427c6a09c87 |
14 | 2b2695bc1bc3 |
15 | 149b9217c15b |
hex | a4e75dcacef |
11332101123311 has 2 divisors, whose sum is σ = 11332101123312. Its totient is φ = 11332101123310.
The previous prime is 11332101123293. The next prime is 11332101123341. The reversal of 11332101123311 is 11332110123311.
It is a weak prime.
It is an emirp because it is prime and its reverse (11332110123311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11332101123311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11332101123341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666050561655 + 5666050561656.
It is an arithmetic number, because the mean of its divisors is an integer number (5666050561656).
Almost surely, 211332101123311 is an apocalyptic number.
11332101123311 is a deficient number, since it is larger than the sum of its proper divisors (1).
11332101123311 is an equidigital number, since it uses as much as digits as its factorization.
11332101123311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 11332101123311 its reverse (11332110123311), we get a palindrome (22664211246622).
Subtracting 11332101123311 from its reverse (11332110123311), we obtain a square (9000000 = 30002).
The spelling of 11332101123311 in words is "eleven trillion, three hundred thirty-two billion, one hundred one million, one hundred twenty-three thousand, three hundred eleven".
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