11332222101131 has 2 divisors, whose sum is σ = 11332222101132. Its totient is φ = 11332222101130.

The previous prime is 11332222101127. The next prime is 11332222101133. The reversal of 11332222101131 is 13110122223311.

It is a happy number.

11332222101131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11332222101131 - 2² = 11332222101127 is a prime.

It is a super-2 number, since 2×11332222101131² (a number of 27 digits) contains 22 as substring.

Together with 11332222101133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11332222101097 and 11332222101106.

It is not a weakly prime, because it can be changed into another prime (11332222101133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666111050565 + 5666111050566.

It is an arithmetic number, because the mean of its divisors is an integer number (5666111050566).

Almost surely, 2^{11332222101131} is an apocalyptic number.

11332222101131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11332222101131 is an equidigital number, since it uses as much as digits as its factorization.

11332222101131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 11332222101131 its reverse (13110122223311), we get a palindrome (24442344324442).

The spelling of 11332222101131 in words is "eleven trillion, three hundred thirty-two billion, two hundred twenty-two million, one hundred one thousand, one hundred thirty-one".