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11334210000 = 243543710211
BaseRepresentation
bin10101000111001001…
…00101000111010000
31002020220022112011120
422203210211013100
5141203024210000
65112403242240
7550605124011
oct124344450720
932226275146
1011334210000
114896958803
122243979380
1310b8242749
1479742b008
154650a96a0
hex2a39251d0

11334210000 has 200 divisors, whose sum is σ = 37580895264. Its totient is φ = 2940480000.

The previous prime is 11334209993. The next prime is 11334210059. The reversal of 11334210000 is 1243311.

It is a tau number, because it is divible by the number of its divisors (200).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 1104895 + ... + 1115105.

Almost surely, 211334210000 is an apocalyptic number.

11334210000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11334210000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18790447632).

11334210000 is an abundant number, since it is smaller than the sum of its proper divisors (26246685264).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11334210000 is a wasteful number, since it uses less digits than its factorization.

11334210000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10279 (or 10258 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 11334210000 its reverse (1243311), we get a palindrome (11335453311).

The spelling of 11334210000 in words is "eleven billion, three hundred thirty-four million, two hundred ten thousand".