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113352100535 = 546723485209
BaseRepresentation
bin110100110010001001…
…1111100101010110111
3101211120200222022211202
41221210103330222313
53324121114204120
6124023452523115
711121653646212
oct1514423745267
9354520868752
10113352100535
114408833a933
1219b7548049b
13a8c5b2174b
1456b4482779
152e3653c875
hex1a644fcab7

113352100535 has 8 divisors (see below), whose sum is σ = 136025712240. Its totient is φ = 90679552704.

The previous prime is 113352100517. The next prime is 113352100559. The reversal of 113352100535 is 535001253311.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113352100535 - 236 = 44632623799 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113352100498 and 113352100507.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8990 + ... + 476219.

It is an arithmetic number, because the mean of its divisors is an integer number (17003214030).

Almost surely, 2113352100535 is an apocalyptic number.

113352100535 is a deficient number, since it is larger than the sum of its proper divisors (22673611705).

113352100535 is an equidigital number, since it uses as much as digits as its factorization.

113352100535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 531937.

The product of its (nonzero) digits is 6750, while the sum is 29.

Adding to 113352100535 its reverse (535001253311), we get a palindrome (648353353846).

The spelling of 113352100535 in words is "one hundred thirteen billion, three hundred fifty-two million, one hundred thousand, five hundred thirty-five".

Divisors: 1 5 46723 233615 485209 2426045 22670420107 113352100535