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11341102013 is a prime number
BaseRepresentation
bin10101000111111101…
…10111101110111101
31002021101021200020022
422203332313232331
5141211310231023
65113211101525
7551020530233
oct124376675675
932241250208
1011341102013
11489a83588a
1222461418a5
1310b97b6767
14798302953
154659bb7c8
hex2a3fb7bbd

11341102013 has 2 divisors, whose sum is σ = 11341102014. Its totient is φ = 11341102012.

The previous prime is 11341102009. The next prime is 11341102051. The reversal of 11341102013 is 31020114311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7228060324 + 4113041689 = 85018^2 + 64133^2 .

It is a cyclic number.

It is not a de Polignac number, because 11341102013 - 22 = 11341102009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11341101982 and 11341102000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11341102313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670551006 + 5670551007.

It is an arithmetic number, because the mean of its divisors is an integer number (5670551007).

Almost surely, 211341102013 is an apocalyptic number.

It is an amenable number.

11341102013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11341102013 is an equidigital number, since it uses as much as digits as its factorization.

11341102013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11341102013 its reverse (31020114311), we get a palindrome (42361216324).

The spelling of 11341102013 in words is "eleven billion, three hundred forty-one million, one hundred two thousand, thirteen".