Base | Representation |
---|---|
bin | 10000100000001111101… |
… | …011011100101111011111 |
3 | 11000102101202222200022112 |
4 | 100200033223130233133 |
5 | 122040201402224203 |
6 | 2225003020304235 |
7 | 144636623314262 |
oct | 20401753345737 |
9 | 4012352880275 |
10 | 1134134414303 |
11 | 3a7a90345750 |
12 | 1639773a207b |
13 | 82c43894867 |
14 | 3cc6ca54cd9 |
15 | 1e77c5516d8 |
hex | 1080fadcbdf |
1134134414303 has 16 divisors (see below), whose sum is σ = 1277089051392. Its totient is φ = 998205624000.
The previous prime is 1134134414251. The next prime is 1134134414311. The reversal of 1134134414303 is 3034144314311.
It is a cyclic number.
It is not a de Polignac number, because 1134134414303 - 230 = 1133060672479 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1134134414303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1134134414363) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9539051 + ... + 9657212.
It is an arithmetic number, because the mean of its divisors is an integer number (79818065712).
Almost surely, 21134134414303 is an apocalyptic number.
1134134414303 is a deficient number, since it is larger than the sum of its proper divisors (142954637089).
1134134414303 is a wasteful number, since it uses less digits than its factorization.
1134134414303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19196446.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 1134134414303 its reverse (3034144314311), we get a palindrome (4168278728614).
The spelling of 1134134414303 in words is "one trillion, one hundred thirty-four billion, one hundred thirty-four million, four hundred fourteen thousand, three hundred three".
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