11343310040 has 16 divisors (see below), whose sum is σ = 25522447680. Its totient is φ = 4537324000.

The previous prime is 11343310007. The next prime is 11343310049. The reversal of 11343310040 is 4001334311.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 11343309994 and 11343310021.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11343310049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141791336 + ... + 141791415.

It is an arithmetic number, because the mean of its divisors is an integer number (1595152980).

Almost surely, 2^11343310040 is an apocalyptic number.

11343310040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11343310040 is an abundant number, since it is smaller than the sum of its proper divisors (14179137640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11343310040 is a wasteful number, since it uses less digits than its factorization.

11343310040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 283582762 (or 283582758 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 11343310040 its reverse (4001334311), we get a palindrome (15344644351).

The spelling of 11343310040 in words is "eleven billion, three hundred forty-three million, three hundred ten thousand, forty".