Base | Representation |
---|---|
bin | 10101001000001110… |
… | …10010110111011101 |
3 | 1002021112102212102202 |
4 | 22210013102313131 |
5 | 141212341412201 |
6 | 5113330301245 |
7 | 551045355341 |
oct | 124407226735 |
9 | 32245385382 |
10 | 11343310301 |
11 | 48a1003a14 |
12 | 2246a27825 |
13 | 10ba0aa93b |
14 | 798719621 |
15 | 465ca5c6b |
hex | 2a41d2ddd |
11343310301 has 8 divisors (see below), whose sum is σ = 11452257144. Its totient is φ = 11234513920.
The previous prime is 11343310291. The next prime is 11343310309. The reversal of 11343310301 is 10301334311.
It can be written as a sum of positive squares in 4 ways, for example, as 918696100 + 10424614201 = 30310^2 + 102101^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11343310301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11343310309) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 116915 + ... + 190671.
It is an arithmetic number, because the mean of its divisors is an integer number (1431532143).
Almost surely, 211343310301 is an apocalyptic number.
It is an amenable number.
11343310301 is a deficient number, since it is larger than the sum of its proper divisors (108946843).
11343310301 is a wasteful number, since it uses less digits than its factorization.
11343310301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75231.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 11343310301 its reverse (10301334311), we get a palindrome (21644644612).
The spelling of 11343310301 in words is "eleven billion, three hundred forty-three million, three hundred ten thousand, three hundred one".
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