Base | Representation |
---|---|
bin | 10101001000001110… |
… | …10011000011000000 |
3 | 1002021112102220110010 |
4 | 22210013103003000 |
5 | 141212341423130 |
6 | 5113330304520 |
7 | 551045360445 |
oct | 124407230300 |
9 | 32245386403 |
10 | 11343311040 |
11 | 48a1004526 |
12 | 2246a28140 |
13 | 10ba0ab089 |
14 | 7987199cc |
15 | 465ca60b0 |
hex | 2a41d30c0 |
11343311040 has 56 divisors (see below), whose sum is σ = 36015015600. Its totient is φ = 3024882688.
The previous prime is 11343311039. The next prime is 11343311041. The reversal of 11343311040 is 4011334311.
It is an interprime number because it is at equal distance from previous prime (11343311039) and next prime (11343311041).
It is a junction number, because it is equal to n+sod(n) for n = 11343310998 and 11343311016.
It is not an unprimeable number, because it can be changed into a prime (11343311041) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5907015 + ... + 5908934.
Almost surely, 211343311040 is an apocalyptic number.
11343311040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11343311040 is an abundant number, since it is smaller than the sum of its proper divisors (24671704560).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11343311040 is a wasteful number, since it uses less digits than its factorization.
11343311040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11815969 (or 11815959 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 11343311040 its reverse (4011334311), we get a palindrome (15354645351).
The spelling of 11343311040 in words is "eleven billion, three hundred forty-three million, three hundred eleven thousand, forty".
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