Base | Representation |
---|---|
bin | 11001110010101010111011… |
… | …011010010011010010011100 |
3 | 112212122002222212110211022120 |
4 | 121302222323122103102130 |
5 | 104331442224003142000 |
6 | 1041130301240542540 |
7 | 32615165124453561 |
oct | 3162527332232234 |
9 | 485562885424276 |
10 | 113433230521500 |
11 | 3316384348197a |
12 | 10880153481a50 |
13 | 4b3a927b9b766 |
14 | 20022aa4d6868 |
15 | d1a9d2da56a0 |
hex | 672abb69349c |
113433230521500 has 96 divisors (see below), whose sum is σ = 330324864070656. Its totient is φ = 30248193268800.
The previous prime is 113433230521411. The next prime is 113433230521511. The reversal of 113433230521500 is 5125032334311.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 69038529 + ... + 70662471.
It is an arithmetic number, because the mean of its divisors is an integer number (3440884000736).
Almost surely, 2113433230521500 is an apocalyptic number.
113433230521500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113433230521500 is an abundant number, since it is smaller than the sum of its proper divisors (216891633549156).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113433230521500 is a wasteful number, since it uses less digits than its factorization.
113433230521500 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1670532 (or 1670520 counting only the distinct ones).
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 113433230521500 its reverse (5125032334311), we get a palindrome (118558262855811).
The spelling of 113433230521500 in words is "one hundred thirteen trillion, four hundred thirty-three billion, two hundred thirty million, five hundred twenty-one thousand, five hundred".
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