Base | Representation |
---|---|
bin | 110100110101000101… |
… | …1111111000001110101 |
3 | 101211211120110111102112 |
4 | 1221222023333001311 |
5 | 3324321333120331 |
6 | 124041333420405 |
7 | 11124261560222 |
oct | 1515213770165 |
9 | 354746414375 |
10 | 113450676341 |
11 | 44128a49342 |
12 | 19ba249a705 |
13 | a910386c22 |
14 | 56c35c2949 |
15 | 2e4001032b |
hex | 1a6a2ff075 |
113450676341 has 2 divisors, whose sum is σ = 113450676342. Its totient is φ = 113450676340.
The previous prime is 113450676263. The next prime is 113450676343. The reversal of 113450676341 is 143676054311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 70674095716 + 42776580625 = 265846^2 + 206825^2 .
It is a cyclic number.
It is not a de Polignac number, because 113450676341 - 214 = 113450659957 is a prime.
Together with 113450676343, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113450676343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56725338170 + 56725338171.
It is an arithmetic number, because the mean of its divisors is an integer number (56725338171).
Almost surely, 2113450676341 is an apocalyptic number.
It is an amenable number.
113450676341 is a deficient number, since it is larger than the sum of its proper divisors (1).
113450676341 is an equidigital number, since it uses as much as digits as its factorization.
113450676341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 181440, while the sum is 41.
The spelling of 113450676341 in words is "one hundred thirteen billion, four hundred fifty million, six hundred seventy-six thousand, three hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.089 sec. • engine limits •