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113450676341 is a prime number
BaseRepresentation
bin110100110101000101…
…1111111000001110101
3101211211120110111102112
41221222023333001311
53324321333120331
6124041333420405
711124261560222
oct1515213770165
9354746414375
10113450676341
1144128a49342
1219ba249a705
13a910386c22
1456c35c2949
152e4001032b
hex1a6a2ff075

113450676341 has 2 divisors, whose sum is σ = 113450676342. Its totient is φ = 113450676340.

The previous prime is 113450676263. The next prime is 113450676343. The reversal of 113450676341 is 143676054311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70674095716 + 42776580625 = 265846^2 + 206825^2 .

It is a cyclic number.

It is not a de Polignac number, because 113450676341 - 214 = 113450659957 is a prime.

Together with 113450676343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113450676343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56725338170 + 56725338171.

It is an arithmetic number, because the mean of its divisors is an integer number (56725338171).

Almost surely, 2113450676341 is an apocalyptic number.

It is an amenable number.

113450676341 is a deficient number, since it is larger than the sum of its proper divisors (1).

113450676341 is an equidigital number, since it uses as much as digits as its factorization.

113450676341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 181440, while the sum is 41.

The spelling of 113450676341 in words is "one hundred thirteen billion, four hundred fifty million, six hundred seventy-six thousand, three hundred forty-one".