Base | Representation |
---|---|
bin | 110100110101000101… |
… | …1111111000001110111 |
3 | 101211211120110111102121 |
4 | 1221222023333001313 |
5 | 3324321333120333 |
6 | 124041333420411 |
7 | 11124261560224 |
oct | 1515213770167 |
9 | 354746414377 |
10 | 113450676343 |
11 | 44128a49344 |
12 | 19ba249a707 |
13 | a910386c24 |
14 | 56c35c294b |
15 | 2e4001032d |
hex | 1a6a2ff077 |
113450676343 has 2 divisors, whose sum is σ = 113450676344. Its totient is φ = 113450676342.
The previous prime is 113450676341. The next prime is 113450676371. The reversal of 113450676343 is 343676054311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113450676343 - 21 = 113450676341 is a prime.
Together with 113450676341, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 113450676343.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113450676341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56725338171 + 56725338172.
It is an arithmetic number, because the mean of its divisors is an integer number (56725338172).
Almost surely, 2113450676343 is an apocalyptic number.
113450676343 is a deficient number, since it is larger than the sum of its proper divisors (1).
113450676343 is an equidigital number, since it uses as much as digits as its factorization.
113450676343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 43.
The spelling of 113450676343 in words is "one hundred thirteen billion, four hundred fifty million, six hundred seventy-six thousand, three hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.182 sec. • engine limits •