1135043324335 has 16 divisors (see below), whose sum is σ = 1406382243840. Its totient is φ = 878497535520.

The previous prime is 1135043324299. The next prime is 1135043324347. The reversal of 1135043324335 is 5334233405311.

It is a happy number.

It is a de Polignac number, because none of the positive numbers 2^k-1135043324335 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1135043324294 and 1135043324303.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 466525 + ... + 1577254.

It is an arithmetic number, because the mean of its divisors is an integer number (87898890240).

Almost surely, 2^{1135043324335} is an apocalyptic number.

1135043324335 is a deficient number, since it is larger than the sum of its proper divisors (271338919505).

1135043324335 is a wasteful number, since it uses less digits than its factorization.

1135043324335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2047398.

The product of its (nonzero) digits is 194400, while the sum is 37.

Adding to 1135043324335 its reverse (5334233405311), we get a palindrome (6469276729646).

The spelling of 1135043324335 in words is "one trillion, one hundred thirty-five billion, forty-three million, three hundred twenty-four thousand, three hundred thirty-five".