113535000415303 has 4 divisors (see below), whose sum is σ = 114659109330408. Its totient is φ = 112410891500200.

The previous prime is 113535000415271. The next prime is 113535000415337. The reversal of 113535000415303 is 303514000535311.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113535000415303 - 2⁵ = 113535000415271 is a prime.

It is a super-3 number, since 3×113535000415303³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113535000415363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 562054457401 + ... + 562054457602.

It is an arithmetic number, because the mean of its divisors is an integer number (28664777332602).

Almost surely, 2^{113535000415303} is an apocalyptic number.

113535000415303 is a deficient number, since it is larger than the sum of its proper divisors (1124108915105).

113535000415303 is a wasteful number, since it uses less digits than its factorization.

113535000415303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1124108915104.

The product of its (nonzero) digits is 40500, while the sum is 34.

The spelling of 113535000415303 in words is "one hundred thirteen trillion, five hundred thirty-five billion, four hundred fifteen thousand, three hundred three".