113550402013 has 4 divisors (see below), whose sum is σ = 114367311520. Its totient is φ = 112733492508.

The previous prime is 113550401911. The next prime is 113550402029. The reversal of 113550402013 is 310204055311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 310204055311 = 587 ⋅528456653.

It is a cyclic number.

It is not a de Polignac number, because 113550402013 - 2¹³ = 113550393821 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113550402073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 408454545 + ... + 408454822.

It is an arithmetic number, because the mean of its divisors is an integer number (28591827880).

Almost surely, 2^113550402013 is an apocalyptic number.

It is an amenable number.

113550402013 is a deficient number, since it is larger than the sum of its proper divisors (816909507).

113550402013 is an equidigital number, since it uses as much as digits as its factorization.

113550402013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 816909506.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 113550402013 its reverse (310204055311), we get a palindrome (423754457324).

The spelling of 113550402013 in words is "one hundred thirteen billion, five hundred fifty million, four hundred two thousand, thirteen".