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11355111534132 = 22322361224818079
BaseRepresentation
bin1010010100111101000101…
…1000111010111000110100
31111012112112020122201022100
42211033101120322320310
52442020232023043012
640052244412102100
72251244151340422
oct245172130727064
944175466581270
1011355111534132
113688748485533
121334843a64930
13644a22ca2992
142b3839c20112
1514a58c3468dc
hexa53d163ae34

11355111534132 has 72 divisors (see below), whose sum is σ = 30442166576640. Its totient is φ = 3561118355520.

The previous prime is 11355111534127. The next prime is 11355111534133. The reversal of 11355111534132 is 23143511155311.

11355111534132 is a `hidden beast` number, since 1 + 1 + 3 + 5 + 5 + 111 + 534 + 1 + 3 + 2 = 666.

11355111534132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11355111534133) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 112358532 + ... + 112459547.

It is an arithmetic number, because the mean of its divisors is an integer number (422807869120).

Almost surely, 211355111534132 is an apocalyptic number.

11355111534132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

11355111534132 is an abundant number, since it is smaller than the sum of its proper divisors (19087055042508).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11355111534132 is a wasteful number, since it uses less digits than its factorization.

11355111534132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 224818173 (or 224818168 counting only the distinct ones).

The product of its digits is 27000, while the sum is 36.

Adding to 11355111534132 its reverse (23143511155311), we get a palindrome (34498622689443).

The spelling of 11355111534132 in words is "eleven trillion, three hundred fifty-five billion, one hundred eleven million, five hundred thirty-four thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 9 12 18 23 36 46 61 69 92 122 138 183 207 244 276 366 414 549 732 828 1098 1403 2196 2806 4209 5612 8418 12627 16836 25254 50508 224818079 449636158 674454237 899272316 1348908474 2023362711 2697816948 4046725422 5170815817 8093450844 10341631634 13713902819 15512447451 20683263268 27427805638 31024894902 41141708457 46537342353 54855611276 62049789804 82283416914 93074684706 123425125371 164566833828 186149369412 246850250742 315419764837 493700501484 630839529674 946259294511 1261679059348 1892518589022 2838777883533 3785037178044 5677555767066 11355111534132