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113553443032000 = 265317249114811
BaseRepresentation
bin11001110100011010111000…
…101000101000101111000000
3112220001121021200112002102021
4121310122320220220233000
5104340424422404011000
61041301422004131224
732626652114110246
oct3164327050505700
9486047250462367
10113553443032000
11331aa821294304
121089b502396b14
134b4907510058a
142008031b5a796
15d1dbbb83711a
hex6746b8a28bc0

113553443032000 has 168 divisors, whose sum is σ = 298730235190608. Its totient is φ = 42749530624000.

The previous prime is 113553443031989. The next prime is 113553443032013. The reversal of 113553443032000 is 230344355311.

113553443032000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (34).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 22245406 + ... + 26869405.

Almost surely, 2113553443032000 is an apocalyptic number.

113553443032000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

113553443032000 is an abundant number, since it is smaller than the sum of its proper divisors (185176792158608).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113553443032000 is an equidigital number, since it uses as much as digits as its factorization.

113553443032000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49114872 (or 49114835 counting only the distinct ones).

The product of its (nonzero) digits is 64800, while the sum is 34.

Adding to 113553443032000 its reverse (230344355311), we get a palindrome (113783787387311).

The spelling of 113553443032000 in words is "one hundred thirteen trillion, five hundred fifty-three billion, four hundred forty-three million, thirty-two thousand".