Base | Representation |
---|---|
bin | 10101001011001010… |
… | …01110000011100111 |
3 | 1002100020202210020112 |
4 | 22211211032003213 |
5 | 141240142312020 |
6 | 5120010123235 |
7 | 551464554200 |
oct | 124545160347 |
9 | 32306683215 |
10 | 11367932135 |
11 | 49039a073a |
12 | 225312051b |
13 | 10c221b981 |
14 | 79bac85a7 |
15 | 46801b2c5 |
hex | 2a594e0e7 |
11367932135 has 12 divisors (see below), whose sum is σ = 15868705608. Its totient is φ = 7795153296.
The previous prime is 11367932131. The next prime is 11367932141. The reversal of 11367932135 is 53123976311.
11367932135 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11367932135 - 22 = 11367932131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11367932092 and 11367932101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11367932131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 23199617 + ... + 23200106.
It is an arithmetic number, because the mean of its divisors is an integer number (1322392134).
Almost surely, 211367932135 is an apocalyptic number.
11367932135 is a deficient number, since it is larger than the sum of its proper divisors (4500773473).
11367932135 is an equidigital number, since it uses as much as digits as its factorization.
11367932135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46399742 (or 46399735 counting only the distinct ones).
The product of its digits is 102060, while the sum is 41.
The spelling of 11367932135 in words is "eleven billion, three hundred sixty-seven million, nine hundred thirty-two thousand, one hundred thirty-five".
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