1139705069413 has 2 divisors, whose sum is σ = 1139705069414. Its totient is φ = 1139705069412.

The previous prime is 1139705069411. The next prime is 1139705069431. The reversal of 1139705069413 is 3149605079311.

Together with next prime (1139705069431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1129507705089 + 10197364324 = 1062783^2 + 100982^2 .

It is a cyclic number.

It is not a de Polignac number, because 1139705069413 - 2¹ = 1139705069411 is a prime.

It is a super-2 number, since 2×1139705069413² (a number of 25 digits) contains 22 as substring.

Together with 1139705069411, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1139705069411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 569852534706 + 569852534707.

It is an arithmetic number, because the mean of its divisors is an integer number (569852534707).

Almost surely, 2^{1139705069413} is an apocalyptic number.

It is an amenable number.

1139705069413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1139705069413 is an equidigital number, since it uses as much as digits as its factorization.

1139705069413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 612360, while the sum is 49.

The spelling of 1139705069413 in words is "one trillion, one hundred thirty-nine billion, seven hundred five million, sixty-nine thousand, four hundred thirteen".