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1139705069431 is a prime number
BaseRepresentation
bin10000100101011011101…
…101110011111101110111
311000221210000011021112211
4100211123231303331313
5122133103444210211
62231323454554251
7145224645151315
oct20453355637567
94027700137484
101139705069431
113aa389888365
12164a70b08987
1383620a162b6
143d23a8210b5
151e9a662ae21
hex1095bb73f77

1139705069431 has 2 divisors, whose sum is σ = 1139705069432. Its totient is φ = 1139705069430.

The previous prime is 1139705069413. The next prime is 1139705069449. The reversal of 1139705069431 is 1349605079311.

Together with previous prime (1139705069413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (1139705069413) and next prime (1139705069449).

It is a cyclic number.

It is not a de Polignac number, because 1139705069431 - 213 = 1139705061239 is a prime.

It is a super-2 number, since 2×11397050694312 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1139705069411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 569852534715 + 569852534716.

It is an arithmetic number, because the mean of its divisors is an integer number (569852534716).

Almost surely, 21139705069431 is an apocalyptic number.

1139705069431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1139705069431 is an equidigital number, since it uses as much as digits as its factorization.

1139705069431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 612360, while the sum is 49.

The spelling of 1139705069431 in words is "one trillion, one hundred thirty-nine billion, seven hundred five million, sixty-nine thousand, four hundred thirty-one".