11400014303 has 2 divisors, whose sum is σ = 11400014304. Its totient is φ = 11400014302.

The previous prime is 11400014281. The next prime is 11400014357. The reversal of 11400014303 is 30341000411.

It is a weak prime.

It is an emirp because it is prime and its reverse (30341000411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11400014303 - 2⁸ = 11400014047 is a prime.

It is a super-2 number, since 2×11400014303² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11400014903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5700007151 + 5700007152.

It is an arithmetic number, because the mean of its divisors is an integer number (5700007152).

Almost surely, 2^11400014303 is an apocalyptic number.

11400014303 is a deficient number, since it is larger than the sum of its proper divisors (1).

11400014303 is an equidigital number, since it uses as much as digits as its factorization.

11400014303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 11400014303 its reverse (30341000411), we get a palindrome (41741014714).

The spelling of 11400014303 in words is "eleven billion, four hundred million, fourteen thousand, three hundred three".