Base | Representation |
---|---|
bin | 10101001111000111… |
… | …10111110000111001 |
3 | 1002102120020120102101 |
4 | 22213203313300321 |
5 | 141322142224423 |
6 | 5123153503401 |
7 | 552350014066 |
oct | 124743676071 |
9 | 32376216371 |
10 | 11401133113 |
11 | 4920708067 |
12 | 2262271b61 |
13 | 10c9074916 |
14 | 7a228bc6d |
15 | 46adc87ad |
hex | 2a78f7c39 |
11401133113 has 4 divisors (see below), whose sum is σ = 12071788020. Its totient is φ = 10730478208.
The previous prime is 11401133111. The next prime is 11401133209. The reversal of 11401133113 is 31133110411.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31133110411 = 13 ⋅2394854647.
It can be written as a sum of positive squares in 2 ways, for example, as 3363652009 + 8037481104 = 57997^2 + 89652^2 .
It is a cyclic number.
It is not a de Polignac number, because 11401133113 - 21 = 11401133111 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11401133111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335327428 + ... + 335327461.
It is an arithmetic number, because the mean of its divisors is an integer number (3017947005).
Almost surely, 211401133113 is an apocalyptic number.
It is an amenable number.
11401133113 is a deficient number, since it is larger than the sum of its proper divisors (670654907).
11401133113 is an equidigital number, since it uses as much as digits as its factorization.
11401133113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 670654906.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 11401133113 its reverse (31133110411), we get a palindrome (42534243524).
The spelling of 11401133113 in words is "eleven billion, four hundred one million, one hundred thirty-three thousand, one hundred thirteen".
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