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1140123443303 = 13292631299701
BaseRepresentation
bin10000100101110100101…
…001110010000001100111
311000222212011101212121102
4100211310221302001213
5122134433100141203
62231433202110315
7145241215240235
oct20456451620147
94028764355542
101140123443303
113aa583a62899
12164b6904b39b
13836895bbac0
143d27a209955
151e9cd21d888
hex10974a72067

1140123443303 has 8 divisors (see below), whose sum is σ = 1227833539296. Its totient is φ = 1052414532000.

The previous prime is 1140123443287. The next prime is 1140123443309. The reversal of 1140123443303 is 3033443210411.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1140123443303 - 24 = 1140123443287 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1140123443309) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3654353 + ... + 3954053.

It is an arithmetic number, because the mean of its divisors is an integer number (153479192412).

Almost surely, 21140123443303 is an apocalyptic number.

1140123443303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1140123443303 is a deficient number, since it is larger than the sum of its proper divisors (87710095993).

1140123443303 is a wasteful number, since it uses less digits than its factorization.

1140123443303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 592345.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 1140123443303 its reverse (3033443210411), we get a palindrome (4173566653714).

The spelling of 1140123443303 in words is "one trillion, one hundred forty billion, one hundred twenty-three million, four hundred forty-three thousand, three hundred three".

Divisors: 1 13 292631 299701 3804203 3896113 87701803331 1140123443303