Base | Representation |
---|---|
bin | 11001111011000110011101… |
… | …000010100001000110111100 |
3 | 112221200111022001101111101011 |
4 | 121323012131002201012330 |
5 | 104420440141114231012 |
6 | 1042252345530525004 |
7 | 33005064031136443 |
oct | 3173063502410674 |
9 | 487614261344334 |
10 | 114012541555132 |
11 | 333674a1452860 |
12 | 10954489596764 |
13 | 4b8044b4a611c |
14 | 2022344b8dd5a |
15 | d2aadb7641a7 |
hex | 67b19d0a11bc |
114012541555132 has 48 divisors (see below), whose sum is σ = 218146607588448. Its totient is φ = 51708107013120.
The previous prime is 114012541555127. The next prime is 114012541555163. The reversal of 114012541555132 is 231555145210411.
It is a super-2 number, since 2×1140125415551322 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 482011278 + ... + 482247754.
It is an arithmetic number, because the mean of its divisors is an integer number (4544720991426).
Almost surely, 2114012541555132 is an apocalyptic number.
It is an amenable number.
114012541555132 is a deficient number, since it is larger than the sum of its proper divisors (104134066033316).
114012541555132 is a wasteful number, since it uses less digits than its factorization.
114012541555132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 260926 (or 260924 counting only the distinct ones).
The product of its (nonzero) digits is 120000, while the sum is 40.
Adding to 114012541555132 its reverse (231555145210411), we get a palindrome (345567686765543).
The spelling of 114012541555132 in words is "one hundred fourteen trillion, twelve billion, five hundred forty-one million, five hundred fifty-five thousand, one hundred thirty-two".
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