1140129133 has 32 divisors (see below), whose sum is σ = 1380500352. Its totient is φ = 927763200.

The previous prime is 1140129131. The next prime is 1140129161. The reversal of 1140129133 is 3319210411.

It is not a de Polignac number, because 1140129133 - 2¹ = 1140129131 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1140129098 and 1140129107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1140129131) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 964803 + ... + 965983.

It is an arithmetic number, because the mean of its divisors is an integer number (43140636).

Almost surely, 2^1140129133 is an apocalyptic number.

1140129133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1140129133 is a deficient number, since it is larger than the sum of its proper divisors (240371219).

1140129133 is a wasteful number, since it uses less digits than its factorization.

1140129133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1405.

The product of its (nonzero) digits is 648, while the sum is 25.

The square root of 1140129133 is about 33765.7982728085. The cubic root of 1140129133 is about 1044.6833691940.

Adding to 1140129133 its reverse (3319210411), we get a palindrome (4459339544).

The spelling of 1140129133 in words is "one billion, one hundred forty million, one hundred twenty-nine thousand, one hundred thirty-three".