114013133525130 has 48 divisors (see below), whose sum is σ = 318306054417120. Its totient is φ = 26060144805408.

The previous prime is 114013133525077. The next prime is 114013133525243. The reversal of 114013133525130 is 31525331310411.

It is a junction number, because it is equal to n+sod(n) for n = 114013133525091 and 114013133525100.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 38779975920 + ... + 38779978859.

It is an arithmetic number, because the mean of its divisors is an integer number (6631376133690).

Almost surely, 2^{114013133525130} is an apocalyptic number.

114013133525130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

114013133525130 is an abundant number, since it is smaller than the sum of its proper divisors (204292920891990).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

114013133525130 is a wasteful number, since it uses less digits than its factorization.

114013133525130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77559954803 (or 77559954796 counting only the distinct ones).

The product of its (nonzero) digits is 16200, while the sum is 33.

Adding to 114013133525130 its reverse (31525331310411), we get a palindrome (145538464835541).

The spelling of 114013133525130 in words is "one hundred fourteen trillion, thirteen billion, one hundred thirty-three million, five hundred twenty-five thousand, one hundred thirty".