11401331403 has 64 divisors (see below), whose sum is σ = 19981688832. Its totient is φ = 5606599680.

The previous prime is 11401331371. The next prime is 11401331467. The reversal of 11401331403 is 30413310411.

It is not a de Polignac number, because 11401331403 - 2⁵ = 11401331371 is a prime.

It is a super-2 number, since 2×11401331403² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a self number, because there is not a number n which added to its sum of digits gives 11401331403.

It is not an unprimeable number, because it can be changed into a prime (11401331483) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 504300 + ... + 526422.

It is an arithmetic number, because the mean of its divisors is an integer number (312213888).

Almost surely, 2^11401331403 is an apocalyptic number.

11401331403 is a deficient number, since it is larger than the sum of its proper divisors (8580357429).

11401331403 is a wasteful number, since it uses less digits than its factorization.

11401331403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22264.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 11401331403 its reverse (30413310411), we get a palindrome (41814641814).

The spelling of 11401331403 in words is "eleven billion, four hundred one million, three hundred thirty-one thousand, four hundred three".