Base | Representation |
---|---|
bin | 10101001111001110… |
… | …10011011111101101 |
3 | 1002102121221022000110 |
4 | 22213213103133231 |
5 | 141322410030013 |
6 | 5123225050233 |
7 | 552360453051 |
oct | 124747233755 |
9 | 32377838013 |
10 | 11402033133 |
11 | 4921172287 |
12 | 2262626979 |
13 | 10c92cb48a |
14 | 7a2443c61 |
15 | 46b0052c3 |
hex | 2a79d37ed |
11402033133 has 64 divisors (see below), whose sum is σ = 17045913600. Its totient is φ = 6746224320.
The previous prime is 11402033131. The next prime is 11402033147. The reversal of 11402033133 is 33133020411.
It is not a de Polignac number, because 11402033133 - 21 = 11402033131 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11402033131) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 23803588 + ... + 23804066.
It is an arithmetic number, because the mean of its divisors is an integer number (266342400).
Almost surely, 211402033133 is an apocalyptic number.
It is an amenable number.
11402033133 is a deficient number, since it is larger than the sum of its proper divisors (5643880467).
11402033133 is a wasteful number, since it uses less digits than its factorization.
11402033133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 862.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 11402033133 its reverse (33133020411), we get a palindrome (44535053544).
It can be divided in two parts, 114020 and 33133, that added together give a triangular number (147153 = T542).
The spelling of 11402033133 in words is "eleven billion, four hundred two million, thirty-three thousand, one hundred thirty-three".
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