Base | Representation |
---|---|
bin | 10101001111010111… |
… | …10101100001111101 |
3 | 1002102201011122121212 |
4 | 22213223311201331 |
5 | 141323211033432 |
6 | 5123310334205 |
7 | 552403531421 |
oct | 124753654175 |
9 | 32381148555 |
10 | 11403221117 |
11 | 4921903892 |
12 | 2262aba365 |
13 | 10c9626122 |
14 | 7a2672b81 |
15 | 46b18c2b2 |
hex | 2a7af587d |
11403221117 has 2 divisors, whose sum is σ = 11403221118. Its totient is φ = 11403221116.
The previous prime is 11403221107. The next prime is 11403221191. The reversal of 11403221117 is 71112230411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11088300601 + 314920516 = 105301^2 + 17746^2 .
It is a cyclic number.
It is not a de Polignac number, because 11403221117 - 24 = 11403221101 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11403221092 and 11403221101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11403221107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701610558 + 5701610559.
It is an arithmetic number, because the mean of its divisors is an integer number (5701610559).
Almost surely, 211403221117 is an apocalyptic number.
It is an amenable number.
11403221117 is a deficient number, since it is larger than the sum of its proper divisors (1).
11403221117 is an equidigital number, since it uses as much as digits as its factorization.
11403221117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 336, while the sum is 23.
Adding to 11403221117 its reverse (71112230411), we get a palindrome (82515451528).
The spelling of 11403221117 in words is "eleven billion, four hundred three million, two hundred twenty-one thousand, one hundred seventeen".
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