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11404020353 = 116715473569
BaseRepresentation
bin10101001111011101…
…11000101010000001
31002102202200020222012
422213232320222001
5141323412122403
65123335422305
7552413400515
oct124756705201
932382606865
1011404020353
1149222aa310
122263224995
1310c9845b4b
147a2800145
1546b298ed8
hex2a7bb8a81

11404020353 has 8 divisors (see below), whose sum is σ = 12626433120. Its totient is φ = 10212554880.

The previous prime is 11404020307. The next prime is 11404020409. The reversal of 11404020353 is 35302040411.

11404020353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11404020353 - 26 = 11404020289 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11404020253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7736048 + ... + 7737521.

It is an arithmetic number, because the mean of its divisors is an integer number (1578304140).

Almost surely, 211404020353 is an apocalyptic number.

It is an amenable number.

11404020353 is a deficient number, since it is larger than the sum of its proper divisors (1222412767).

11404020353 is a wasteful number, since it uses less digits than its factorization.

11404020353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15473647.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 11404020353 its reverse (35302040411), we get a palindrome (46706060764).

The spelling of 11404020353 in words is "eleven billion, four hundred four million, twenty thousand, three hundred fifty-three".

Divisors: 1 11 67 737 15473569 170209259 1036729123 11404020353