Search a number
-
+
114101130000 = 24354111326597
BaseRepresentation
bin110101001000011110…
…1010001001100010000
3101220111220101222002210
41222100331101030100
53332134342130000
6124230051112120
711146350413454
oct1522075211420
9356456358083
10114101130000
1144432127850
121a1442a2640
13a9b5069550
145745b40664
152e7c197350
hex1a90f51310

114101130000 has 400 divisors, whose sum is σ = 432743927616. Its totient is φ = 25532160000.

The previous prime is 114101129971. The next prime is 114101130023. The reversal of 114101130000 is 31101411.

It is a tau number, because it is divible by the number of its divisors (400).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 4276702 + ... + 4303298.

Almost surely, 2114101130000 is an apocalyptic number.

114101130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 114101130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (216371963808).

114101130000 is an abundant number, since it is smaller than the sum of its proper divisors (318642797616).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

114101130000 is a wasteful number, since it uses less digits than its factorization.

114101130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26652 (or 26631 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 114101130000 its reverse (31101411), we get a palindrome (114132231411).

The spelling of 114101130000 in words is "one hundred fourteen billion, one hundred one million, one hundred thirty thousand".