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1141014441013 is a prime number
BaseRepresentation
bin10000100110101001110…
…000101010110000110101
311001002011020222020200121
4100212221300222300311
5122143244144103023
62232101431211541
7145302254503216
oct20465160526065
94032136866617
101141014441013
113aa9a09a6637
12165177516bb1
138379c082a95
143d3226a140d
151ea3156cd5d
hex109a9c2ac35

1141014441013 has 2 divisors, whose sum is σ = 1141014441014. Its totient is φ = 1141014441012.

The previous prime is 1141014441011. The next prime is 1141014441023. The reversal of 1141014441013 is 3101444101411.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 832369749649 + 308644691364 = 912343^2 + 555558^2 .

It is an emirp because it is prime and its reverse (3101444101411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1141014441013 - 21 = 1141014441011 is a prime.

Together with 1141014441011, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1141014441011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570507220506 + 570507220507.

It is an arithmetic number, because the mean of its divisors is an integer number (570507220507).

Almost surely, 21141014441013 is an apocalyptic number.

It is an amenable number.

1141014441013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141014441013 is an equidigital number, since it uses as much as digits as its factorization.

1141014441013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 1141014441013 its reverse (3101444101411), we get a palindrome (4242458542424).

The spelling of 1141014441013 in words is "one trillion, one hundred forty-one billion, fourteen million, four hundred forty-one thousand, thirteen".