1141101331133 has 4 divisors (see below), whose sum is σ = 1142551270080. Its totient is φ = 1139651392188.

The previous prime is 1141101331109. The next prime is 1141101331141. The reversal of 1141101331133 is 3311331011411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1141101331133 - 2²⁸ = 1140832895677 is a prime.

It is a super-2 number, since 2×1141101331133² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1141101331099 and 1141101331108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1141101331933) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 724968293 + ... + 724969866.

It is an arithmetic number, because the mean of its divisors is an integer number (285637817520).

Almost surely, 2^{1141101331133} is an apocalyptic number.

It is an amenable number.

1141101331133 is a deficient number, since it is larger than the sum of its proper divisors (1449938947).

1141101331133 is an equidigital number, since it uses as much as digits as its factorization.

1141101331133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1449938946.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 1141101331133 its reverse (3311331011411), we get a palindrome (4452432342544).

The spelling of 1141101331133 in words is "one trillion, one hundred forty-one billion, one hundred one million, three hundred thirty-one thousand, one hundred thirty-three".