Base | Representation |
---|---|
bin | 1010011000001101101111… |
… | …0101100110101001110000 |
3 | 1111101220002200002201121221 |
4 | 2212003123311212221300 |
5 | 2443424434034303212 |
6 | 40134110301554424 |
7 | 2255266140343315 |
oct | 246033365465160 |
9 | 44356080081557 |
10 | 11411121400432 |
11 | 36aa47a5a8036 |
12 | 1343675575a14 |
13 | 64a0aab841c0 |
14 | 2b64307aad0c |
15 | 14bc69622807 |
hex | a60dbd66a70 |
11411121400432 has 40 divisors (see below), whose sum is σ = 23916513939584. Its totient is φ = 5243054033664.
The previous prime is 11411121400429. The next prime is 11411121400529. The reversal of 11411121400432 is 23400412111411.
11411121400432 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 11411121400397 and 11411121400406.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 122960703 + ... + 123053470.
Almost surely, 211411121400432 is an apocalyptic number.
It is an amenable number.
11411121400432 is an abundant number, since it is smaller than the sum of its proper divisors (12505392539152).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11411121400432 is a wasteful number, since it uses less digits than its factorization.
11411121400432 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 246014417 (or 246014411 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 11411121400432 its reverse (23400412111411), we get a palindrome (34811533511843).
The spelling of 11411121400432 in words is "eleven trillion, four hundred eleven billion, one hundred twenty-one million, four hundred thousand, four hundred thirty-two".
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