Search a number
-
+
114121344221 is a prime number
BaseRepresentation
bin110101001001000101…
…0011000010011011101
3101220120022102221210122
41222102022120103131
53332210031003341
6124232052244325
711150014264163
oct1522212302335
9356508387718
10114121344221
1144442584015
121a14b0106a5
13a9b92c6321
1457486c3233
152e7dd3b94b
hex1a922984dd

114121344221 has 2 divisors, whose sum is σ = 114121344222. Its totient is φ = 114121344220.

The previous prime is 114121344193. The next prime is 114121344223. The reversal of 114121344221 is 122443121411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81789708121 + 32331636100 = 285989^2 + 179810^2 .

It is a cyclic number.

It is not a de Polignac number, because 114121344221 - 26 = 114121344157 is a prime.

Together with 114121344223, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114121344223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57060672110 + 57060672111.

It is an arithmetic number, because the mean of its divisors is an integer number (57060672111).

Almost surely, 2114121344221 is an apocalyptic number.

It is an amenable number.

114121344221 is a deficient number, since it is larger than the sum of its proper divisors (1).

114121344221 is an equidigital number, since it uses as much as digits as its factorization.

114121344221 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1536, while the sum is 26.

Adding to 114121344221 its reverse (122443121411), we get a palindrome (236564465632).

The spelling of 114121344221 in words is "one hundred fourteen billion, one hundred twenty-one million, three hundred forty-four thousand, two hundred twenty-one".