Base | Representation |
---|---|
bin | 10101010000100011… |
… | …11110111110110111 |
3 | 1002110101222201022010 |
4 | 22220101332332313 |
5 | 141333241040203 |
6 | 5124304535303 |
7 | 552554531451 |
oct | 125021767667 |
9 | 32411881263 |
10 | 11413221303 |
11 | 4927514100 |
12 | 2266321533 |
13 | 10cb717ab3 |
14 | 7a3b172d1 |
15 | 46beb5303 |
hex | 2a847efb7 |
11413221303 has 24 divisors (see below), whose sum is σ = 17710754544. Its totient is φ = 6510211840.
The previous prime is 11413221301. The next prime is 11413221319. The reversal of 11413221303 is 30312231411.
It is not a de Polignac number, because 11413221303 - 21 = 11413221301 is a prime.
It is a super-2 number, since 2×114132213032 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11413221303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11413221301) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 918576 + ... + 930917.
It is an arithmetic number, because the mean of its divisors is an integer number (737948106).
Almost surely, 211413221303 is an apocalyptic number.
11413221303 is a deficient number, since it is larger than the sum of its proper divisors (6297533241).
11413221303 is a wasteful number, since it uses less digits than its factorization.
11413221303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1849535 (or 1849524 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 11413221303 its reverse (30312231411), we get a palindrome (41725452714).
The spelling of 11413221303 in words is "eleven billion, four hundred thirteen million, two hundred twenty-one thousand, three hundred three".
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