11414433101 has 2 divisors, whose sum is σ = 11414433102. Its totient is φ = 11414433100.

The previous prime is 11414433083. The next prime is 11414433109. The reversal of 11414433101 is 10133441411.

11414433101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6472202500 + 4942230601 = 80450^2 + 70301^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11414433101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11414433109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5707216550 + 5707216551.

It is an arithmetic number, because the mean of its divisors is an integer number (5707216551).

Almost surely, 2^11414433101 is an apocalyptic number.

It is an amenable number.

11414433101 is a deficient number, since it is larger than the sum of its proper divisors (1).

11414433101 is an equidigital number, since it uses as much as digits as its factorization.

11414433101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 11414433101 its reverse (10133441411), we get a palindrome (21547874512).

The spelling of 11414433101 in words is "eleven billion, four hundred fourteen million, four hundred thirty-three thousand, one hundred one".