Base | Representation |
---|---|
bin | 10101010000101101… |
… | …00110110101001111 |
3 | 1002110111021021120121 |
4 | 22220112212311033 |
5 | 141334043324403 |
6 | 5124350525411 |
7 | 552601036423 |
oct | 125026466517 |
9 | 32414237517 |
10 | 11414433103 |
11 | 4928171597 |
12 | 2266806867 |
13 | 10cba50538 |
14 | 7a3d50b83 |
15 | 46c1543bd |
hex | 2a85a6d4f |
11414433103 has 4 divisors (see below), whose sum is σ = 12015192760. Its totient is φ = 10813673448.
The previous prime is 11414433101. The next prime is 11414433109. The reversal of 11414433103 is 30133441411.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30133441411 = 349 ⋅86342239.
It is a cyclic number.
It is not a de Polignac number, because 11414433103 - 21 = 11414433101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11414433101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 300379800 + ... + 300379837.
It is an arithmetic number, because the mean of its divisors is an integer number (3003798190).
Almost surely, 211414433103 is an apocalyptic number.
11414433103 is a deficient number, since it is larger than the sum of its proper divisors (600759657).
11414433103 is an equidigital number, since it uses as much as digits as its factorization.
11414433103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 600759656.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11414433103 its reverse (30133441411), we get a palindrome (41547874514).
The spelling of 11414433103 in words is "eleven billion, four hundred fourteen million, four hundred thirty-three thousand, one hundred three".
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