11422413204133 has 2 divisors, whose sum is σ = 11422413204134. Its totient is φ = 11422413204132.

The previous prime is 11422413204079. The next prime is 11422413204143. The reversal of 11422413204133 is 33140231422411.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11243299728609 + 179113475524 = 3353103^2 + 423218^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11422413204133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11422413204095 and 11422413204104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11422413204143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5711206602066 + 5711206602067.

It is an arithmetic number, because the mean of its divisors is an integer number (5711206602067).

Almost surely, 2^{11422413204133} is an apocalyptic number.

It is an amenable number.

11422413204133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11422413204133 is an equidigital number, since it uses as much as digits as its factorization.

11422413204133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 11422413204133 its reverse (33140231422411), we get a palindrome (44562644626544).

The spelling of 11422413204133 in words is "eleven trillion, four hundred twenty-two billion, four hundred thirteen million, two hundred four thousand, one hundred thirty-three".