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114225044010151 is a prime number
BaseRepresentation
bin11001111110001100010111…
…001011000011010010100111
3112222102210210201020200221011
4121332030113023003102213
5104432430342231311101
61042534132200003051
733026326034200564
oct3176142713032247
9488383721220834
10114225044010151
1133439629559508
12109896b4160487
134b974b5a91479
14202c7434c386b
15d313c7609751
hex67e3172c34a7

114225044010151 has 2 divisors, whose sum is σ = 114225044010152. Its totient is φ = 114225044010150.

The previous prime is 114225044010139. The next prime is 114225044010163. The reversal of 114225044010151 is 151010440522411.

It is a balanced prime because it is at equal distance from previous prime (114225044010139) and next prime (114225044010163).

It is a cyclic number.

It is not a de Polignac number, because 114225044010151 - 219 = 114225043485863 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114225044010851) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57112522005075 + 57112522005076.

It is an arithmetic number, because the mean of its divisors is an integer number (57112522005076).

Almost surely, 2114225044010151 is an apocalyptic number.

114225044010151 is a deficient number, since it is larger than the sum of its proper divisors (1).

114225044010151 is an equidigital number, since it uses as much as digits as its factorization.

114225044010151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6400, while the sum is 31.

Adding to 114225044010151 its reverse (151010440522411), we get a palindrome (265235484532562).

The spelling of 114225044010151 in words is "one hundred fourteen trillion, two hundred twenty-five billion, forty-four million, ten thousand, one hundred fifty-one".