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1142341155119 is a prime number
BaseRepresentation
bin10000100111111000110…
…101101011100100101111
311001012120201102022022002
4100213320311223210233
5122204003313430434
62232441223242515
7145350164415323
oct20477065534457
94035521368262
101142341155119
1140051188a57a
121654878a943b
1383950bb2208
143d40a977983
151eaacc8857e
hex109f8d6b92f

1142341155119 has 2 divisors, whose sum is σ = 1142341155120. Its totient is φ = 1142341155118.

The previous prime is 1142341155107. The next prime is 1142341155121. The reversal of 1142341155119 is 9115511432411.

It is a strong prime.

It is an emirp because it is prime and its reverse (9115511432411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1142341155119 - 212 = 1142341151023 is a prime.

It is a super-2 number, since 2×11423411551192 (a number of 25 digits) contains 22 as substring.

Together with 1142341155121, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1142341155149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571170577559 + 571170577560.

It is an arithmetic number, because the mean of its divisors is an integer number (571170577560).

Almost surely, 21142341155119 is an apocalyptic number.

1142341155119 is a deficient number, since it is larger than the sum of its proper divisors (1).

1142341155119 is an equidigital number, since it uses as much as digits as its factorization.

1142341155119 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 21600, while the sum is 38.

The spelling of 1142341155119 in words is "one trillion, one hundred forty-two billion, three hundred forty-one million, one hundred fifty-five thousand, one hundred nineteen".