Base | Representation |
---|---|
bin | 11001111110011011011010… |
… | …011101100110010110011000 |
3 | 112222111100112000121212211001 |
4 | 121332123122131212112120 |
5 | 104433211442031100402 |
6 | 1042545404001114344 |
7 | 33030440365152241 |
oct | 3176333235462630 |
9 | 488440460555731 |
10 | 114241205331352 |
11 | 33445472169310 |
12 | 109908646289b4 |
13 | 4b98b900ab618 |
14 | 202d437a49cc8 |
15 | d31a21369187 |
hex | 67e6da766598 |
114241205331352 has 32 divisors (see below), whose sum is σ = 233689674542400. Its totient is φ = 51924602423200.
The previous prime is 114241205331317. The next prime is 114241205331371. The reversal of 114241205331352 is 253133502142411.
It is a super-2 number, since 2×1142412053313522 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38798974 + ... + 41639437.
It is an arithmetic number, because the mean of its divisors is an integer number (7302802329450).
Almost surely, 2114241205331352 is an apocalyptic number.
It is an amenable number.
114241205331352 is an abundant number, since it is smaller than the sum of its proper divisors (119448469211048).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114241205331352 is a wasteful number, since it uses less digits than its factorization.
114241205331352 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 80454567 (or 80454563 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 37.
Adding to 114241205331352 its reverse (253133502142411), we get a palindrome (367374707473763).
The spelling of 114241205331352 in words is "one hundred fourteen trillion, two hundred forty-one billion, two hundred five million, three hundred thirty-one thousand, three hundred fifty-two".
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