Base | Representation |
---|---|
bin | 11001111111010010010001… |
… | …000010011011001100001111 |
3 | 112222200222112201000010020122 |
4 | 121333102101002123030033 |
5 | 104440143102332410020 |
6 | 1043032424210535155 |
7 | 33034624051200224 |
oct | 3177222102331417 |
9 | 488628481003218 |
10 | 114300103013135 |
11 | 33468446398386 |
12 | 109a01612974bb |
13 | 4ba15b83558c0 |
14 | 2032223d5994b |
15 | d3331be29125 |
hex | 67f49109b30f |
114300103013135 has 32 divisors (see below), whose sum is σ = 150628403483712. Its totient is φ = 82755351244800.
The previous prime is 114300103013119. The next prime is 114300103013141. The reversal of 114300103013135 is 531310301003411.
It is a happy number.
It is not a de Polignac number, because 114300103013135 - 24 = 114300103013119 is a prime.
It is a super-3 number, since 3×1143001030131353 (a number of 43 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 84037916 + ... + 85387185.
It is an arithmetic number, because the mean of its divisors is an integer number (4707137608866).
Almost surely, 2114300103013135 is an apocalyptic number.
114300103013135 is a deficient number, since it is larger than the sum of its proper divisors (36328300470577).
114300103013135 is a wasteful number, since it uses less digits than its factorization.
114300103013135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 169425323.
The product of its (nonzero) digits is 1620, while the sum is 26.
Adding to 114300103013135 its reverse (531310301003411), we get a palindrome (645610404016546).
The spelling of 114300103013135 in words is "one hundred fourteen trillion, three hundred billion, one hundred three million, thirteen thousand, one hundred thirty-five".
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