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11431126615787 is a prime number
BaseRepresentation
bin1010011001011000010000…
…1111011100011011101011
31111110210201212102221222222
42212112010033130123223
52444241421403201122
640151215335104255
72256604655021324
oct246260417343353
944423655387888
1011431126615787
113707a05a6946a
12134751921208b
1364bc48666938
142b73ab64d44b
1514c53aa6db42
hexa65843dc6eb

11431126615787 has 2 divisors, whose sum is σ = 11431126615788. Its totient is φ = 11431126615786.

The previous prime is 11431126615771. The next prime is 11431126615789. The reversal of 11431126615787 is 78751662113411.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11431126615787 - 24 = 11431126615771 is a prime.

Together with 11431126615789, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11431126615789) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5715563307893 + 5715563307894.

It is an arithmetic number, because the mean of its divisors is an integer number (5715563307894).

Almost surely, 211431126615787 is an apocalyptic number.

11431126615787 is a deficient number, since it is larger than the sum of its proper divisors (1).

11431126615787 is an equidigital number, since it uses as much as digits as its factorization.

11431126615787 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1693440, while the sum is 53.

The spelling of 11431126615787 in words is "eleven trillion, four hundred thirty-one billion, one hundred twenty-six million, six hundred fifteen thousand, seven hundred eighty-seven".