Base | Representation |
---|---|
bin | 10000101000100110110… |
… | …110110011101000110111 |
3 | 11001021120112011100211120 |
4 | 100220212312303220313 |
5 | 122212043434432411 |
6 | 2233050003035023 |
7 | 145405260620460 |
oct | 20504666635067 |
9 | 4037515140746 |
10 | 1143113202231 |
11 | 400878668a40 |
12 | 16566236ba73 |
13 | 83a44b28b20 |
14 | 3d481307d67 |
15 | 1eb0593d106 |
hex | 10a26db3a37 |
1143113202231 has 128 divisors (see below), whose sum is σ = 2194767912960. Its totient is φ = 509496998400.
The previous prime is 1143113202229. The next prime is 1143113202277. The reversal of 1143113202231 is 1322023113411.
It is not a de Polignac number, because 1143113202231 - 21 = 1143113202229 is a prime.
It is a super-2 number, since 2×11431132022312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1143113202331) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 2835016 + ... + 3213026.
It is an arithmetic number, because the mean of its divisors is an integer number (17146624320).
Almost surely, 21143113202231 is an apocalyptic number.
1143113202231 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1143113202231 is a deficient number, since it is larger than the sum of its proper divisors (1051654710729).
1143113202231 is a wasteful number, since it uses less digits than its factorization.
1143113202231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 378117.
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 1143113202231 its reverse (1322023113411), we get a palindrome (2465136315642).
The spelling of 1143113202231 in words is "one trillion, one hundred forty-three billion, one hundred thirteen million, two hundred two thousand, two hundred thirty-one".
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