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11432040113 = 135571578793
BaseRepresentation
bin10101010010110011…
…10001011010110001
31002111201101210212002
422221121301122301
5141403100240423
65130220143345
7553203511004
oct125131613261
932451353762
1011432040113
1149370a7a3a
122270697b55
1311025a66a0
147a641553b
1546d981228
hex2a96716b1

11432040113 has 8 divisors (see below), whose sum is σ = 12333538728. Its totient is φ = 10533700224.

The previous prime is 11432040101. The next prime is 11432040223. The reversal of 11432040113 is 31104023411.

11432040113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 5071504 + 11426968609 = 2252^2 + 106897^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11432040113 - 218 = 11431777969 is a prime.

It is a super-2 number, since 2×114320401132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11432040913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 782156 + ... + 796637.

It is an arithmetic number, because the mean of its divisors is an integer number (1541692341).

Almost surely, 211432040113 is an apocalyptic number.

11432040113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11432040113 is a deficient number, since it is larger than the sum of its proper divisors (901498615).

11432040113 is a wasteful number, since it uses less digits than its factorization.

11432040113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1579363.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 11432040113 its reverse (31104023411), we get a palindrome (42536063524).

The spelling of 11432040113 in words is "eleven billion, four hundred thirty-two million, forty thousand, one hundred thirteen".

Divisors: 1 13 557 7241 1578793 20524309 879387701 11432040113