Base | Representation |
---|---|
bin | 10101010010110100… |
… | …11000101111010011 |
3 | 1002111201200222210012 |
4 | 22221122120233103 |
5 | 141403120414141 |
6 | 5130223425135 |
7 | 553205051366 |
oct | 125132305723 |
9 | 32451628705 |
10 | 11432201171 |
11 | 49371a7a46 |
12 | 22707551ab |
13 | 1102631aa1 |
14 | 7a64580dd |
15 | 46d9b3ceb |
hex | 2a9698bd3 |
11432201171 has 2 divisors, whose sum is σ = 11432201172. Its totient is φ = 11432201170.
The previous prime is 11432201117. The next prime is 11432201201. The reversal of 11432201171 is 17110223411.
Together with previous prime (11432201117) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11432201171 - 222 = 11428006867 is a prime.
It is a super-2 number, since 2×114322011712 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11432203171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5716100585 + 5716100586.
It is an arithmetic number, because the mean of its divisors is an integer number (5716100586).
Almost surely, 211432201171 is an apocalyptic number.
11432201171 is a deficient number, since it is larger than the sum of its proper divisors (1).
11432201171 is an equidigital number, since it uses as much as digits as its factorization.
11432201171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 336, while the sum is 23.
Adding to 11432201171 its reverse (17110223411), we get a palindrome (28542424582).
The spelling of 11432201171 in words is "eleven billion, four hundred thirty-two million, two hundred one thousand, one hundred seventy-one".
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