Base | Representation |
---|---|
bin | 10101010010110100… |
… | …11000101111110001 |
3 | 1002111201200222211022 |
4 | 22221122120233301 |
5 | 141403120414301 |
6 | 5130223425225 |
7 | 553205051441 |
oct | 125132305761 |
9 | 32451628738 |
10 | 11432201201 |
11 | 49371a7a73 |
12 | 2270755215 |
13 | 1102631ac5 |
14 | 7a6458121 |
15 | 46d9b3d1b |
hex | 2a9698bf1 |
11432201201 has 2 divisors, whose sum is σ = 11432201202. Its totient is φ = 11432201200.
The previous prime is 11432201171. The next prime is 11432201203. The reversal of 11432201201 is 10210223411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8902111201 + 2530090000 = 94351^2 + 50300^2 .
It is a cyclic number.
It is not a de Polignac number, because 11432201201 - 222 = 11428006897 is a prime.
Together with 11432201203, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11432201201.
It is not a weakly prime, because it can be changed into another prime (11432201203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5716100600 + 5716100601.
It is an arithmetic number, because the mean of its divisors is an integer number (5716100601).
Almost surely, 211432201201 is an apocalyptic number.
It is an amenable number.
11432201201 is a deficient number, since it is larger than the sum of its proper divisors (1).
11432201201 is an equidigital number, since it uses as much as digits as its factorization.
11432201201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 11432201201 its reverse (10210223411), we get a palindrome (21642424612).
The spelling of 11432201201 in words is "eleven billion, four hundred thirty-two million, two hundred one thousand, two hundred one".
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